When a body falls freely, its kinetic energy increases while its potential energy decreases. But the total mechanical energy is conserved during the free fall.
Hence E = P.E + K.E is constant.
E = mgh + ½ mv^2
Hence, option C is correct.
When a body falls freely, its kinetic energy increases while its potential energy decreases. But the total mechanical energy is conserved during the free fall.
Hence E = P.E + K.E is constant.
E = mgh + ½ mv^2
Hence, option C is correct.