Heat transfer will continue between the two bodies until they have achieved thermal equilibrium. This means that the temperature of the two bodies is the same and hence, the average translational kinetic energy is the same.
The relation between average translational kinetic energy is given by the equation:
Ek = 2RT / 3NA Where Ek is the average translational kinetic energy and T is the thermodynamic temperature.
Heat transfer will continue between the two bodies until they have achieved thermal equilibrium. This means that the temperature of the two bodies is the same and hence, the average translational kinetic energy is the same.
The Kelvin temperature of a gas is directly proportional to average translational kinetic energy, not average rotational kinetic energy.
Heat transfer will continue between the two bodies until they have achieved thermal equilibrium. This means that the temperature of the two bodies is the same and hence, the average translational kinetic energy is the same.
The Kelvin temperature of a gas is directly proportional to average translational kinetic energy, not average translational potential energy.
Heat transfer will continue between the two bodies until they have achieved thermal equilibrium. This means that the temperature of the two bodies is the same and hence, the average translational kinetic energy is the same.
The Kelvin temperature of a gas is directly proportional to average translational kinetic energy, not average vibrational kinetic energy.
Heat transfer will continue between the two bodies until they have achieved thermal equilibrium. This means that the temperature of the two bodies is the same and hence, the average translational kinetic energy is the same.
The relation between average translational kinetic energy is given by the equation:
Ek = 2RT / 3NA Where Ek is the average translational kinetic energy and T is the thermodynamic temperature.